Question

Va rog :)))) Dau coronița

Answer 1

Răspuns:

Explicație pas cu pas:

x ≤ -4

(-∞_______________]-4_______________

2x ≤ -18

x ≤ -9

(-∞____________]-9_______________

-2x ≤ 6

2x ≥ 6

x ≥ 3

____________[3_______________+∞)

4 - 2x ≤ 6

2x ≥ 4 - 6

2x ≥ -2

x ≥ -1

____________[-1_____________________+∞)

______________________________________________

N = multimea numerelor naturale (intregi si pozitive)

3x + 12 ≤ 2x - 3

3x - 2x ≤ -12 - 3

x ≤ -15

nu are solutii in N

____________

3x + 6 > 6x - 2

6x - 3x < 6 + 2

3x < 8

x < 8/3

x = {0, 1, 2}

______________

-5(x - 2) ≤ -4(x - 7) + 1

-5x + 10 ≤ -4x + 28 + 1

-4x + 5x ≥ 10 - 28 - 1

x ≥ -19

x = N

________________

3x - x/2 ≤ (1 - x)/-3

6x/2 - x/2 ≤ -1/3 + x/3

5x/2 - x/3 ≤ -1/3

15x/6 - 2x/6 ≤ -2/6

13x/6 ≤ -2/6

13x ≤ -2

x ≤ -2/13

nu are solutii in N