Question

va rog de la ex 26 in jos...

Answer 1

|---------------------------------------| a
b a-b
|-------------------------------|====|

|----------------------------------------||------------------------|a+b=132
|=====||=====||=====||=====||=====|| 12 (a+b):(a-b)=5si rest 12


. 132-12=120
120:5=24
132-24=108

b=108:2=54
a=132-54=78




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Answer 2

Consideram x , y cele doua numere
Cunoastem ca:
x+y=132
(x+y)/(x-y)=5 r 12  l=>x+y=5(x-y)+12
5(x-y)+12=132
5(x-y)=120
x-y=24 il putem determina pe x din aceasta formula l=>x=24+y
x l----l+24l          }132
y l----l                 }
132-24=108
108/2=54 (numarul y)
x=y+24
x=54+24
x=78

R: x=78 ,y=54