Question

va rog desfășurat dau coroana va rogg va rog am nevoie de toate pana la 17 :40

Answer 1

$28.a) \sqrt{2^{2}*5+2^{2}*11}=\sqrt{4*5+4*11}=\sqrt{20+44}=\sqrt{64}=8 \\b) \sqrt{7^{4}*45+7^{4}*39-7^{4}*3}=\sqrt{7^{4}(45+39-3)=\sqrt{7^4*81}}=7^{2}*9=441\\c) \sqrt{5^{2}*11+19*5^{2}+5^{2}*6}=\sqrt{5^{2}*(11+19+6)}=\sqrt{25*36}=30\\d) \sqrt{3^{4}*19-3^{4}*10}=\sqrt{81*19-81*10}=\sqrt{81*(19-10)}=\sqrt{81*9}=9*3=27\\e) \sqrt{2^{2}*3^{4}+2^{2}*3^{2}+2^{3}*3^{3}}=\sqrt{2^{2}*3^{2}*(3^{2}+1+3*2}=\sqrt{4*9*16}=2*3*4=24\\f) \sqrt{2^{4}*5^{2}+2^{3}*5+1}=\sqrt{(2^{2}*5+1)^{2}}=4*5+1=21$

$g) \sqrt{3^{4}+2*3^{2}*5^{2}+5^{4}}=\sqrt{(3^{2}+5^{2})^{2}}=9+25=36\\h) \sqrt{11^{2}-2*11*15+15^{2}}=\sqrt{(15-11)^{2}}=4\\i) \sqrt{48^{2}-2*48*13+13^{2}}=\sqrt{(48-13)^{2}}=35$

$29. a) \frac{x}{3}=\frac{2}{6}\\\frac{x}{3}=\frac{1}{3}\\x=3\\ b)\frac{5}{x}=\frac{16}{8}\\\frac{5}{x}=2\\x=\frac{5}{2}\\ c)\frac{\frac{5}{10}-2}{8-4}=\frac{x}{27-9-2}\\\frac{\frac{5}{10}\frac{20}{10}}{4}=\frac{x}{16}\\\frac{-15}{10}}:4=\frac{x}{16}\\   \frac{-3}{2}*\frac{1}{4}=\frac{x}{16}\\\frac{-3}{8}=\frac{x}{16}\\ 8x=-48\\x=-6$

$\\d) \frac{\sqrt(700-5*15)}{\sqrt{180+45}}=\frac{3*\sqrt{200+25}}{x}\\\frac{\sqrt(700-75)}{\sqrt{225}}=\frac{3*15}{x}\\\frac{\sqrt{625}}{15}=\frac{45}{x}\\\frac{25}{15}=\frac{45}{x}\\25*x=45*15\\ x=\frac{45*15}{25}=27$