Question

Va rog,doar cei care stiu,sa ma ajute,please...
Ex.incercuit !

Answer 1

⇒5/10·[(2x-√2)/√3]-2/3·[(-1)(2x-√2)/√3]=[(2x-√2)/√3]+1/5   simplificam pe 5/10 cu5
1/2·[(2x-√2)/√3]+2/3·[(2x-√2)/√3]=[(2x-√2)/√3]+1/5
Notam [(2x-√2)/√3]=a
a/2+2a/3=a+1/5
a/2+2a/3-a=1/5
(3a+4a-6a)/6=15
a=15·6
a=90
deci (2x-√2)/√3=90
[√3(2x-√2)/3]=90
2√3x-√6=90·3
2√3x=270+√6
x=(270+√6)/2√3
x=[√3(270+√6)]/6
x=(270√3+3√2)/6
x=3(90+√2)/6
x=(90+√2)/3
x=30+√2/3