Question

Va rog doar testul doi dau coroana este urgent va implor

Answer 1

1.

A={10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95} sau {10,15,20,...,95}

2.

a) = {1,2,3,4,5,6,7,11}

b) = Ø

c) = {8,10}

d) = {1,2,3} int {2,3,4,5} = {2,3}

3.

a) F

b) A

c) A

d) A

e) A

f) F

4.

a)

M9={9,18,27,36...}

D36={1,2,3,4,6,9,12,18,36}

M9 int D36 = {9,18,36}

b)

D100 -> multime finita

c)

3<2n+1<33 |-1

=> 2<2n<32 |÷2

=> 1<n<16

n∈N => n={2,3,4,5,6,7,8,9,10,11,12,13,14,15}

5.

a)

M={0,2,4,6}

P={1,3,5}

b)

M={2,4,6,8}

P={1,2,3,5,7,8,9,10}

c)

M={1,2,3,4,5}

P={1,3,5}

6.

4x+1=4x

1≠0

4x+1=4x+2

1≠2

4x+1=2x+7

2x=6

x=3

12=4x

x=3

12=4x+2

4x=10

x=10/4=5/2 nu este numar natural

12=2x+7

2x=5

x=5/2 nu este număr natural, din nou

27=4x

x=27/4 nu este numar natural

27=4x+2

4x=25

x=25/4 nu este numar natural

27=2x+7

2x=20

x=10

x=3=> C={13,12,27}, D={12,14,13}, ceea ce convin cerintei, avand doua elemente comune

x=10=> C={41,12,27}, D={40,42,27}, ceea ce nu convin cerintei, avand doar un element comun

Raspuns: Da, x fiind 3.