Question

va rog e foarte urgennnt

Answer 1

$\\ j) 4-x=-4 => -x = -4 -4 => -x= -8 => x = 8\\\\ k) 5=x^2 => x=\sqrt{5},\:x=-\sqrt{5}\\\\\\ l) \frac{3}{4}x=-\frac{1}{2} => 4\cdot \frac{3}{4}x=4\left(-\frac{1}{2}\right) => 4\cdot \frac{3}{4}x=4\left(-\frac{1}{2}\right) => \\ \frac{3x}{3}=\frac{-2}{3} => x=-\frac{2}{3}\\\\ o) -3-x=-6=> -x = -6 + 3 => -x= -3 =>x = 3\\\\ p) \sqrt{x} = 9 => \left(\sqrt{x}\right)^2=9^2 => x=81 \\ \\ r) x : 0,6 = 0,2 => x = 0,2 \cdot 0,6 => x = 0,12$