Question

va rog , e ft urgent dau corona cine raspunde cel mai repede ​

Answer 1

$\displaystyle \left\{\begin{array}{ccc}\cfrac{x+3}{y-1}=\cfrac{x}{y-8} \\\\x-4 \cdot y=6 \end{array}\right \Rightarrow \left\{\begin{array}{ccc}(x+3)(y-8)=x(y-1)\\\\ x-4y=6\end{array}\right \Rightarrow \\\\\\ \Rightarrow \left\{\begin{array}{ccc}xy-8x+3y-24=xy-x\\\\ x-4y=6\end{array}\right \Rightarrow \left\{\begin{array}{ccc}xy-8x+3y-xy+x=24\\\\x-4y=6\end{array}\right\Rightarrow$

$\displaystyle \left\{\begin{array}{ccc}-7x+3y=24\\\\x-4y=6\big|\cdot 7\end{array}\right\Rightarrow \left\{\begin{array}{ccc}-7x+3y=24\\\\7x-28y=42\end{array}\right \\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~----------\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~/~-25y=66 \Rightarrow y=-\frac{66}{25} \\\\ x-4y=6 \Rightarrow x-4 \cdot \Bigg(-\frac{66}{25} \Bigg)=6 \Rightarrow x+\frac{264}{25} =6 \Rightarrow 25x+264=150 \Rightarrow \\\\ \Rightarrow 25x=150-264 \Rightarrow 25x=-114 \Rightarrow x=-\frac{114}{25}$