Question

Va rog! E urgent!!!

Answer 1

 

$\displaystyle\\\text{Daca pentru orice }( n\in \mathbb{N}^\ast)\text{ avem ca }\\\\~\left[x_n=\frac{n+1}{1}\cdot\frac{n+2}{3}\cdot\ldots\cdot\frac{n+n}{2n-1}=\prod_{k=1}^n\frac{n+k}{2k-1}\right]\\\\\\\text{atunci valoarea lui }~\Big(x_{2018}\Big)~\text{este:}\\\\\\a)~~\Big(\frac{2019+2019}{2\cdot2019-1} \Big)\\\\\\b)~~\Big(2019\Big)\\\\\\c)~~\Big(2^{2018}\Big)\\\\\\d)~~\Big(1\Big)$

 

 

Acesta este textul descifrat din enuntul problemei.

E scris intr-o alta versiune de LATEX.

Avea putine diferente pe care le-am adaptat.

Doar am decodificat problema, nu am rezolvat-o.

Acum ne putem gandi la rezolvare si eu si altii.