Question

Va rog,e urgent! ....​

Answer 1

Răspuns:

Explicație pas cu pas:

a) xy(4x²-1)/(2x-1)=xy(2x-1)(2x+1)/(2x-1)=xy(2x+1)          x≠1/2

b)  (m²-1)²/(m-1)²=(m-1)²(m+1)²/(m-1)²=(m+1)²       m≠1

c) [x²(x-2)-4(x-2)]/(x-2)²=(x-2)(x²-4)/(x-2)²=(x-2)(x-2)(x+2)/(x-2)²=x+2      x≠2

d) (x-1)³/(x-1)²=x-1       x≠1

e) (2a²+2ab+a²-b²)/(a+b)=[2a(a+b)+(a-b)(a+b)/(a+b)=2a+a-b=3a-b     a≠b

f) (3x²+3x+2x+2)/(x+1)=[3x(x+1)+2(x+1)]/(x+1)= 3x+2         x≠-1