Question

Va rog, e urgent, ex 1!

Answer 1

1) [1,1(6)+1$\frac{1}{4}$ :0,(3)]*(2-4/3)^2=

=[ $\frac{16}{9}$ + $\frac{5}{4}$ : $\frac{3}{9}$ ]* $\frac{4}{9}$=

=( $\frac{16}{9}$ + $\frac{5}{4}$ *  $\frac{9}{3}$ )* $\frac{4}{9}$=

=( $\frac{16}{9}$ +  $\frac{45}{12}$ ) * $\frac{4}{9}$=

=$\frac{597}{108}$ * $\frac{4}{9}$=

= $\frac{597}{27}$ * 9=

=597*3=

=1791