Question

va rog , e urgent!
imi trebuie pana maine dimineata ​

Answer 1

Răspuns:

#include<iostream>

using namespace std;

int main ()

{int a, b, c, d;

cin>>a>>b>>c>>d;

if(((a+b)%2==0)&&((c-d)%2==0))

cout<<"DA" ;

else

if(((a+b) %2!=0)&&((c-d)%2!=0))

cout<<"DA" ;

else

cout<<"NU" ;

return 0;

}