Question

Vă rog e urgent ofer coroană ​

Answer 1

$a) \: \sqrt{2} = 1.414213... \\1.41 = 1.410000... \\ 1.(41) = 1.414141... \\ = > 1.41 < 1.(41) < \sqrt{2} \\ \\ b) \: 2 \sqrt{6} = \sqrt{ {2}^{2} \times 6} = \sqrt{24} \\ 5 = \sqrt{25} \\ 3 \sqrt{3} = \sqrt{ {3}^{2} \times 3 } = \sqrt{27} \\ = > 2 \sqrt{6} < 5 < 3 \sqrt{3}$