Question

Va rog e urgent Please Problema spune Efectuati

Answer 1

j)
(y+2)/(4y+6) : (2y+4)/(2y+3) =
= (y+2))/2(2y+3) × (2y+3)/2(y+2) =
= 1/2×2 =
= 1/4
pe al 2-lea rand s-au simplificat:
(y+2) cu (y+2) si (2y+3) cu (2y+3)
k)
(n+1)/(n+2) × (n+2)/(n+3) : (n+1)/(n+3) =
= (n+1)/(n+2) ×(n+2)/(n+3) × (n+3)/(n+1) =
= (n+1)/(n+1) =
= 1
pe al 2-lea rand s-au simplificat:
(n+2) cu (n+2) si (n+3) cu (n+3)

l) (2m+3)/(6p+4) : (4m+6)/(9p+6) + (3n+3)/(8q+20) × (2q+1)/3(n+1) =

= (2m+3)/2(3p+2) × 3(3p+2)/2(2m+3) + 3(n+1)/4(2q+5) × (2q+1)/3(n+1) =

= 3/2×2 + (2q+1)/4(2q+5) =

= 3/4 + (2q+1)/4(2q+5) =

= 3(2q+5)/4(2q+5) + (2q+1)/4(2q+5) =

= (6q+15+2q+1)/4(2q+5) =

= 8(q+2)/4(2q+5) =

= 2(q+2)/(2q+5)