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Răspunsuri la întrebare
Răspuns:
Explicație:
a.
15 moli Al2O3
masa de oxigen
M= 2.27 + 3.16=102------> 102 g/moli
mAl2O3= n . M
m= 15moli . 102g /moli= 1530 g Al2O3
102 g Al2O3----------------48g O
1530g-----------------------------x
x= 1530 . 48 : 102=720g O
b.
15 moli Ba(OH)2
masa de O
M= 137 + 2.16 + 2=171--------> 171g/moli
mBa(OH)2= n . M
m= 15 moli. 171g/moli=2565 g Ba(OH)2
171g Ba(OH)2 ----------32g O
2565g-----------------------y
y= 2565 . 32 : 171 =480g O
c.
15moli HNO3
masa de O
M=1 + 14 + 3.16= 63------> 63g/moli
m HNO3 = 15moli .63g/moli =945g
63g HNO3-----------48g O
945g------------------------z
z= 945 . 48 : 63 =720 gO
d.
15 moli CaOCl2
masa de O
M= 40 + 16 + 2.35,5= 127--------> 127g/moli
m= 15moli . 127g/moli=1905 g CaOCl2
127g CaOCl2--------------16g O
1905g---------------------------W
W= 1905 .16 : 127=240 gO