va rog e urgentt!!dau coroana
Răspunsuri la întrebare
Răspuns:
a) NaOH
MNaOH=23+16+1=40g/mol
40gNaOH.............23gNa................16gO.................1gH
100gNaOH................x%gNa...............y%O..............z%H
x=100x23/40=calculeaza
y=100x16/40=calculeaza
z=100x1/40=calculeaza
b) NaCl
MNaCl=23+35,5=58,5g/mol
58,5g NaCl.................23gNa.................35,5gCl
100gNaCl....................x%Na.....................y%Cl
x=100x23/58,5=calculeaza
y=100x35,5/58,5=calculeaza
c) H2SO4
MH2SO4=2x1+32+4x16=98g/mol
98gH2SO4.............2gH.............32gS............64gO
100gH2SO4..............x%H...............y%S...............z%O
x=100x2/98=calculeaza
y=100x32/98=calculeaza
z=100x64/98=calculeaza
d) Ca(OH)2
MCa(OH)2=40+2x16+2x1=74g/mol
74gCa(OH)2...............40gCa................32gO..............2gH
100gCa(OH)2................x%Ca...................y%O................z%H
x=100x40/74=calculeaza
y=100x32/74=calculeaza
z=100x2/74=calculeaza
e) Ca3(PO4)2
MCa3(PO4)2=3x40+2x31+8x16=310g/mol
310gCa3(PO4)2............120gCa............62gP................128gO
100gCa3(PO4)2.................x%Ca.............y%P..............z%O
x=100x120/310=calculeaza
y=100x62/310=calculeaza
z=100x128/310=calculeaza
Explicație: