Question

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$\it \Big|\dfrac{\sqrt{27}x}{3}+12\Big|=2\sqrt3$

Answer 1

$|\frac{\sqrt{27}x}{3}+12|=2\sqrt{3}\\\\|\frac{3\sqrt{3}x}{3}+12|=2\sqrt{3}\\\\|\sqrt{3}x+12|=2\sqrt{3}$

• √3x + 12 = + 2√3

x = (2√3 - 12)/√3

x = (2×3 - 12√3)/3

x = 3(2 - 4√3)/3

x₁ = 2 - 4√3

• √3x + 12 = - 2√3

x = (- 12 - 2√3)/√3

x = (-12√3 - 2×3)/3

x = 3(- 4√3 - 2)/3

x₂ = - 2 - 4√3