Question

Va rog!!! efectuati : ( DAU COROANA!!!)
1) (√360 + 2√2 x √405) x ( √810 - √20 x √162)
2) √18 x ( 3√50 + √162 ) - √12 x ( √432-√192)
3) √363 x ( √432 - √75 - √48)
4) 2√108 x ( 5√27 - 6√48 + 7√12 - 4√75)

Answer 1

1) (√360 + 2√2 x √405) x ( √810 - √20 x √162)=
= (6√10 + 2√2 x 9√5) x (9 √10 -2√5 x 9√2)=
= (6√10 + 18√10) x (9√10 -18√10)=
= 24√10 x (-9√10)=-216x10=-2160

2) √18 x ( 3√50 + √162 ) - √12 x ( √432-√192) =
=3√2 x ( 15√2 + 9√2 ) - 2√3 x (12√3-8√3) =
=3√2 x 24√2 - 2√3 x 4√3 =
=144 - 24 =120

3) √363 x ( √432 - √75 - √48) =
= 11√3 x (12 √3 - 5√3 - 4√3) =
=11√3 x 3√3=
=33x3=99

4) 2√108 x ( 5√27 - 6√48 + 7√12 - 4√75) =
=12√3 x ( 15√3 - 24√3 + 14√3 - 20√3) =
=12√3 x ( 29√3 - 44√3) =
=12√3 x ( -15√3) =
=-540