Question

Va rog!!ex 1 si 2 cap coada va rog sami aratati cum ati ajuns la rezultatul respectiv ...Dau 50 puncte

Answer 1

[tex]ex~1.\\ La~trapezul ~dreptunghic~latura ~perpendiculara~este~inaltimea!\\\\ A_{trapez}= \frac{(B+b)*h}{2} = \frac{(AB+CD)*AD}{2}= \\ \\ = \frac{(24+16)*12}{2}= \frac{40*12}{2}=20*12=240 \,cm^{2} [/tex]

[tex]ex~2.\\Se ~aplica~ teorema~ unghiului~ de ~15~ grade~in~~~ triunghiul\\dreptunghic ~care~se ~refera~la ~faptul~ca ~inaltimea ~opusa~ unghiului\\de~15~grade~este~egala~cu ~sfertul ~ipotenuzei.\\ CB= 2*AM\\ CB=2*24\\ CB=48cm\\\\ Inaltimea~~~AD= \frac{48}{2} \\ AD=12cm\\\\ Deci:\\\\ A_{triunghiului~ABC}= \frac{b*h}{2} \\\\ A_{triunghiului~ABC}= \frac{48*12}{2} \\\\ A_{triunghiului~ABC}=288 cm^2[/tex]