Question

Va rog ex 3 imi trebuie urgent
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Answer 1

$\it \sqrt2\cdot\sqrt{2^2}\cdot\sqrt{2^3}\cdot\sqrt{2^4}=\sqrt{2\cdot2^2\cdot2^3\cdot2^4}=\sqrt{2^{1+2+3+4}}=\sqrt{2^{10}}=\\ \\ =\sqrt{(2^5)^2}=2^5=32=\dfrac{32}{1}\in\mathbb{Q}$