Question

va rog,ex 3 si 4
multumesc celui care imi raspunde​

Answer 1

Răspuns:

1.M(SO3)= 32+ 16×3 = 80 g/mol

MCa(OH)2 = 40+ (16+1)×2 = 74 g/mol

MAl2(SO4)3 = 27×2 (32+16×4)3 = 342 g/mol

M(P4) =31×4 =124 g/mol

MCl2 = 35,5 × 2 = 71 g/mol

MFe2O3 = 56×2 + 16×3 = 160g/mol

MO2 = 16×2 = 32g/mol

2) a) 10Cl2 => 10 molecule de Cl2

M(Cl2) = 71 g/mol

masa relativa= 10×71g/mol = 710

b) 3NH3=>3 molecule de NH3

M(NH3)= 17 g/mol

masa relativa = 3×17 g/mol = 51

c)4Al(OH)3 => 4 molecule de Al(OH)3

MAl(OH)3 = 78g/mol

masa relativa = 4×78g/mol = 312