Question

Va rog ex.3.Urgent am nevoie de el!

Answer 1

[19/6+(4/3)la puterea9:(4/3)la puterea8]·(1/50)³=(19/6+4/3)·(1/50)³=9/2·(1/50)³
b)[(2/3)²·(2/3)³]:(4/9)la puterea 5=(2/3)la puterea5:(4/9)la puterea5

Answer 2

a)[19/6+(1 1/3)⁹:(1,(3))⁸]×(0,02)³=
=[19/6+(4/3)⁹:(12/9)⁸]×(2/100)³=
=[19/6+(4/3)⁹:(4/3)⁸]×(1/50)³=
=[19/6+4/3]×(1/50)³=
=(19+8)/6×(1/50)³=
=27/6×(1/50)³=
=9/2×1/125000=
=9/250000=0,000036

b)[(2/3)²×[0,(6)]³]:(4/9)⁵=
=[(2/3)²×(6/9)³]×(3²/2²)⁵=
=[(2/3)²×(2/3)³]×(3/2)¹⁰=
=(2/3)⁵×(3/2)¹⁰=
=(3/2)⁵=243/32

c)5/2×(0,2)² -3,5(6)×(15,07-7/100)=
=5/2×(1/5)² -321/90×(1507/100-7/100)=
=5/2×(1/5)² -107/30×(1500/100)=
=1/10 -107/30 × 15=
=1/10 -107/2 =
=(1-535)/10=
=-534/10=-53,4