Question

Va rog ex 4.Si penultima postare postata!!!!!!!dau coroana!!!

Answer 1

Răspuns:

Explicație pas cu pas:

CD=34

AB=64

AD=40

a. DE║BC

CD║EB⇒ DE=BC si CD=EB

BE=34

AB=64⇒ AE=64-34=30

In ΔDAE aplicam Pitagora

DE²=AD²+AE²

DE²=1600+900=2500

DE=50

b. Notam DQ=x⇒ QE=50-x

TRasam QR║AB

DQ=CR

Aplicam Teorema lui Thales

$\frac{CQ}{QA} =\frac{CR}{RB} \\\frac{CQ}{CA}=\frac{CR}{BC}=\frac{QR}{AB}$

$\frac{CR}{50}=\frac{34}{64} \\CR=\frac{34\cdot 50}{64} =26,56<27$

CR=DQ=26,56<27

Answer 2

Răspuns:

Explicație pas cu pas:

a)

EBCD patrulat cu lat opuse || 2 cate 2, EBCD paralelogram⇒[EB]=34⇒[AE]=64-34=30

⇒[DE]=√(AD²+AE²)=√(40²+30²)=50 (numereb pitagorice)

b) ΔAQE≈ΔCQD

DQ/(50-DQ)=34/30

30DQ=34*50-34DQ

64DQ=34*50

DQ=34*50/64=34*25/32=17*25/16

17*25/16 comparat cu 27

17*25 comparat cu 16*27

425comparat cu 432

da,  este mai mic