Question

Va rog ex 5!!!!!!!!!

Answer 1

Răspuns:

$3\sqrt{27} > (\frac{\sqrt{3} }{18} )^{-1} > \sqrt{75}$

Explicație pas cu pas:

$(\frac{\sqrt{3} }{18} )^{-1} = \frac{18}{\sqrt{3} } = \frac{18\sqrt{3} }{3} = 6\sqrt{3}$

$3\sqrt{27} = 3\sqrt{9*3} = 3*3\sqrt{3} = 9\sqrt{3}$

Ι$-\sqrt{75}$ Ι = $\sqrt{75} = \sqrt{25*3} = 5\sqrt{3}$

Acum e mai simplu sa le comparam:

$9\sqrt{3} > 6\sqrt{3} > 5\sqrt{3}$

adica

$3\sqrt{27} > (\frac{\sqrt{3} }{18} )^{-1} <\sqrt{75}$