Question

Va rog exercițiul 2 !!!

Answer 1

$\displaystyle [0,41(6)+0,291(6)-0,7(2)]:[-0,02(7)] \\ \\ 0,41(6)= \frac{416-41}{900} = \frac{375}{900} ^{(75}= \frac{5}{12} \\ \\ 0,291(6)= \frac{2916-291}{9000} = \frac{2625}{9000} ^{(375}= \frac{7}{24} \\ \\ 0,7(2)= \frac{72-7}{90} = \frac{65}{90} ^{(5}= \frac{13}{18} \\ \\ 0,02(7)= \frac{27-2}{900} = \frac{25}{900} ^{(25}= \frac{1}{36}$

$\displaystyle [0,41(6)+0,291(6)-0,7(2)]:[-0,02(7)] = \\ \\ = \left(\frac{5}{12} + \frac{7}{24} - \frac{13}{18} \right):\left(- \frac{1}{36} \right)= \frac{30+21-52}{72} \cdot (- 36)= \\ \\ = \left(- \frac{1}{72} \right) \cdot (-36)= \frac{36}{72} ^{(36}= \frac{1}{2}$