Question

Vă rog! Exercitiul din imagine!
Mulțumesc anticipat!(+coroană)

Answer 1

7.

a)

4x+7/5-3x+2/2=12/5*x-16/5-3/2(x-3)

4x+7/5-3x+2/2=12/5*x-16/5-3/2*x+9/2

4x+7/5-3x+2/2=12/5*x+13/10-3/2*x - inmultesc totul cu 10 pentru a scapa de numitor.

10*(4x+7/5)-10*(3x+2/2)=10*(12/5*x)+10*(13/10)-10*(3/2*x) - simplific ce se poate.

2(4x+7)-5(3x+2)=24x+13-15x

8x+14-15x-10=24x+13-15x

8x+14-15x-10+15x=24x+13

8x+4=24x+13

8x-24x=13-4

-16x=9

x=-9/16

b)

3/7*x+12/7-2x+9/3=8/7*(x+5)-5/3*(x+3)

3/7*x+12/7-2x+9/3=8/7*x+40/7-5/3*x-5 - il amplific pe 5 cu 7

3/7*x+12/7-2x+9/3=8/7*x+40/7-5/3*x-35/7

3/7*x+12/7-2x+9/3=8/7*x+5/7-5/3*x - inmultesc totul cu 21 pentru a scapa de numitor

21*(3/7*x)+21*(12/7)-21*(2x+9/3)=21*(8/7*x)+21*(5/7)-21*(5/3*x) - simplific ce se poate

9x+3*12-7(2x+9)=3*8x+3*5-7*5x

9x+36-7(2x+9)=24x+15-35x

9x+36-14x-63=24x+15-35x

9x+36-14x-63=-11x+15

-5x-27=-11x+15

-5x+11x=15+27

6x=42

x=42/6

x=7

c)

11/5-4x+4/3+7x+4/5=2x+6/5-2x+5/3 - inmultesc totul cu 15 pentru a scapa de numitor

15*(11/5)-15*(4x+4/3)+15*(7x+4/5)=15*(2x+6/5)-15*(2x+5/3)- simplific ce se poate

33-5(4x+4)+3(7x+4)=3(2x+6)-5(2x+5)

33-20x-20+21x+12=6x+18-10x-25

25+x=-4x-7

x+4x=-7-25

5x=-32

x=-32/5

d)

-2x-10/6+6x+3/7=-5x-5/14+3x-3/21 - inmultesc totul cu 42 ca sa scap de numitor.

42*(-2x-10/6)+42*(6x+3/7)=42*(-5x-5/14)+42*(3x-3/21) - simplific ce se poate.

7(-2x-10)+6(6x+3)=3(-5x-5)+2(3x-3)

-14x-70+36x+18=-15x-15+6x-6

22x-52=-9x-21

22x+9x=-21+52

31x=31

x=31/31

x=1

Sper sa te ajute!