Question

Va rog ,, f) "


E PENTRU MAINE!!!!!!!! ​

Answer 1

Răspuns:

Explicație pas cu pas:

(3^32:3²+2²·2^25-1):[3^(3·10)+2^(3·9)-1]=

(3^30+2^27-1):(3^30+2^27-1)=1

=1

Answer 2

$\it f)\ \ \ = (3^{32-2}+2^{2+25}-1):[(3^3)^{10}]+(2^3)^9-324:324]=\\ \\ \\ =(3^{30}+2^{27}-1):(3^{30}+2^{27}-1)=1$