Question

Va rog, faceti-mi problemele din imagine.

Answer 1

1) a) NaOH + HCl = NaCl + HOH

b) c HCl = 20%
c NaOH = 20 % 
ms NaOH = 200 g
md = c x ms/100 => md NaOH = 20 x 200/100 =40 g
40 g NaOH = 1 mol NaOH
cf. r. chimice: 1 mol NaOH consuma 1 mol HCl
1 mol HCl = 36,5 g
ms = md x 100/c => ms HCl = 36.5 x 100/20 =182.5 g sol. HCl 20%
d=ms/Vs => Vs= ms/d => Vs HCl = 182.5/1.1= 165.9 ml solutie HCl 20%

2) pV=nRT
p= 6 atm
T = 273 K+273 gr C =  546 K
R = 0.082 L x atm/mol x K
n= m/M => n = 2.84 kg / 71 kg/kmol = 0.04 kmol =40 mol Cl2

V=nRT/p => V Cl2 = 40 x 0.082 x 546 / 6 = 298.48 L Cl2

3) 2 Al + 6 HCl = 2 AlCl3 + 3 H2
m Al= 2.7 kg = 2700 g => n Al= 100 mol = 0.1 kmol
2 mol Al .... 3 mol H2
100 mol Al ... x mol H2
x= 100 * 3 / 2=150 mol H2
V= n x 22.4 l/mol
V H2 = 150 mol * 22.4 l/mol = 3360 L = 3.360 m cubi