Question

Vă rog foarte frumos, rezolvare...
x'2-3x+5<0;
x'2-5x+4>0;
x'2-6x+9> sau=0​

Answer 1

x²-3x+5<0

x²-3x+5=0

D=b²-4ac=9-20=-11 => nu are soluții în R => Ø

x²-5x+4>0

x²-5x+4=0

D=b²-4ac=25-16=9

x¹=5+3/2=8/2=4

x²=5-3/2=2/2=1

S: x€(infinit, 1) U (4, -infinit)

x | infinit 1 4 -infinit

____________________

ec|++++++++0-----0++++++++

x²-6x+9>=0

x²-6x+9=0

D=b²-4ac=36-36=0

x¹=x²=6/2=3

x | infinit 3 -infinit

____________________

ec|++++++++++0++++++++++

S: X€R