Question

Va rog frumos aflati A din exercitiul {2+[2222-22-(a+2)]:2-22:2-2}x2=222

Answer 1

{2+[2222-22-(a+2)]÷2-22:2-2}×2=222 {2+[2200-(a+2)]÷2-11-2}×2=222 2+[2200-(a+2)]÷2-11-2=111(de la 222÷2) 2+[2200-(a+2)]÷2-9=111 [2200-(a+2)]÷2-9=109 [2200-(a+2)]÷2=118(109+9) 2200-(a+2)=236(118×2) a+2=1964(2200-236) a=1962(1964-2)

Answer 2

{2+[(2222-a-20)]:2-22:2-2}x2=222
[2+(2202-a):2-13]x2=222
(2+1102-a/2-13)x2=222
4+2204-a-26=222
-a=-1900 inmultesti ecuatia cu -1
 
a=1960