Question

va rog frumos ajutați-mă ​

Answer 1

Răspuns:

a) ma =(32√6 + 2√6 )/2 =34√6/2 =17√6

mg = √32√6*2√6 -la mg e totul sub radical

mg = √64*6 =√64 *√6 =8√6

ma+mg =17√6+8√6=25√6

b) ma =(2√5+8√5)/2=10√5/2=5√5

mg = √2√5*8√5 =√16*5=√16*√5=4√5

ma+mg=5√5+4√5=9√5

c) ma =(4√3+16√3)/2=20√3/2=10√3

mg=√(4√3*16√3) =√64*3=√64*√3=8√3

ma+mg=10√3+8√3=18√3

d) ma =(4√7+36√7)/2 =40√7/2=20√7

mg =√4√7*36√7 =√144*7 =√144*√7=12√7

ma+mg =20√7+12√7=32√7

e) ma = (3√2+27√2)/2=30√2/2=15√2

mg =√3√2*27√2=√81*2=√81*√2=9√2

ma+mg =15√2+9√2=24√2

f)ma =(2√7+32√7)/2 =34√7/2=17√7

mg = √2√7*32√7=√64*7=√64*√7=8√7

ma+mg = 17√7+8√7=25√7

Explicație pas cu pas: