Question

VA ROG FRUMOS AJUTATI°MA!!! 1. Determinati valoarea lui a din :


a. 546+127-96:3+73*2-(62:a+24:2)-5*11=689

b. (324:6+345:5)*2+1237=43*a+1354

VA ROG FRUMOS AM NEVOIE URGENT!!

Answer 1

a. 546+127-96:3+73·2-(62:a+24:2)-5·11=689
 546+127-96:3+73·2-(62:a+24:2)-5·11=689
673-32+146-(62:a+12)-55=689
641+146-(62:a+12)=689+55
787-(62:a+12)=744
62:a+12=787-744
62:a+12=43
62:a=43-12
62:a=31
a=62:31
a=2

b. (324:6+345:5)·2+1237=43·a+1354
(54+69)·2+1237-1354=43·a
123·2+1237-1354=43·a
246+1237-1354=43·a
1483-1354=43·a
129=43·a
43·a=129
a=129:43
a=3