Question

Va rog frumos ajutatima ​.2.4.6.8.10.12

Answer 1

Răspuns:

2) (a+20)×3-10=53,(a+20)×3=53+10,(a+20)=63÷3,a+20=21,a=1

4) 2a+9=16,2a=16-9,2a=7,a=3,5

6) a+a+1+a+2+a+3+a+4=110,5a=110-4-3-2-1, 5a=100

a=20 ,nr sunt 20,21,22,23,24

10) a+b+c=682

a÷b=4 rest6 ,a=4b+6

b÷c=3 rest4 b=3c+4

c+3c+4+4(3c+4)+6=682

4c+12c=682-6-16-4

16c=656

c=41

b=3×41+4=127

a=4×127+6=514