Question

Vă rog frumos ajutațimă, Dau coroană.​

Answer 1

Răspuns:

Explicație pas cu pas:

$\bf \dfrac{7^{n}+2\cdot 7^{n+1} +7^{n+2}}{2^{n+1}+2^{n+2} +2^{n+4}} =\dfrac{7^{n}\cdot\Big(7^{n-n}+2\cdot 7^{n+1-n} +7^{n+2-n}\Big)}{2^{n}\cdot\Big(2^{n+1-n}+2^{n+2-n} +2^{n+4-n}\Big)}=$

$\bf \dfrac{7^{n}\cdot\Big(7^{0}+2\cdot 7^{1} +7^{2}\Big)}{2^{n}\cdot\Big(2^{1}+2^{2} +2^{4}\Big)}=\dfrac{7^{n}\cdot\Big(1+2\cdot 7 +49\Big)}{2^{n}\cdot\Big(2+4 +16\Big)}=$

$\bf \dfrac{7^{n}\cdot64^{\red{(2}}~}{2^{n}\cdot22~}=\dfrac{7^{n}\cdot32}{2^{n}\cdot11~}$

==pav38==

Answer 2

$\frac{7 {}^{n} + 2 \times 7 {}^{n + 1} + 7 {}^{n + 2} }{2 {}^{n + 1} + 2 {}^{n + 2} + 2 {}^{n + 4} } = \frac{(1 + 2 \times 7 + 7 {}^{2}) \times 7 {}^{n} }{(1 + 2 + {2}^{3}) \times 2 {}^{n + 1} } = \frac{(1 + 14 + 49) \times 7 {}^{n} }{(1 + 2 + 8) \times 2 {}^{n + 1} } = \frac{64 \times 7 {}^{n} }{11 \times 2 {}^{n + 1} } = \frac{2 {}^{6} \times 7 {}^{n} }{11 \times 2 {}^{n + 1} } = \frac{7 {}^{n} }{11 \times 2 {}^{n - 5} }$

Daca esti pe telefon, glisează in dreapta pentru a vedea rezolvarea completă