Matematică, întrebare adresată de Choco212, 9 ani în urmă

Va rog frumos ajutatima:
Rezolvati in R ecuatiile:
3(x-2)+7(2x+1)=1+5x-3(6-5x)
2(3x+2)-3(4x-1)=2-3(2x-1)
x-(2x-5)-7(x-1)=4(3-2x)
3x(x+2)+2(x-3)=(x+4)(3x-5)
7-x(4x-3)-2x(5-2x)=3(x+4)
x(3-x)+(2x=7)-x(3+x)=6-2x(x-4)


Choco212: Multumesc tuturor celor care incearca sa ma ajute

Răspunsuri la întrebare

Răspuns de MaVe
3
a) 3(x-2)+7(2x+1)=1+5x-3(6-5x)
3x-6+14x+7=1+5x-18+15x
17x+1=20x-17
20x-17x=1+17
3x=18
x=18/3
x=6
b) 2(3x+2)-3(4x-1)=2x-3(2x-1)
6x+4-12x+3=2x-6x+3
-6x+7=-4x+3
-6x+4x=3-7
-2x=-4
x=-4/-2
x=2
c)x-(2x-5)-7(x-1)=4(3-2x)
x-2x+5-7x+7=12-8x
-x+5-7x+7=12-8x
-8x+12=12-8x
-8x+8x=12-12
0=0
d)3x(x+2)+2(x-3)=(x+4)(3x-5)
3x^2+6x+2x-6=3x^2-5x+12x-20
3x^2-3x^2+8x-6=7x-20
8x-6=7x-20
8x-7x=-20+6
x=-14
e)7-x(4x-3)-2x(5-2x)=3(x+4)
7-4x^2+3x-10x+4x^2=3x+12
7+3x-10x=3x+12
-7x+7=3x+12
3x+7x=7-12
10x=-5
x=-5/10
x=-1/2
f)x(3-x)+(2x-7)-x(3+x)=6-2x(x-4)
3x-x^2+2x-7-3x-x^2=6-2x^2+8x
2x-2x^2-7=6-2x^2+8x
2x-8x-2x^2+2x^2=6+7
-6x=13
x=-13/6

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