Question

Va rog frumos ,am nevoie de ajutooor!
Stabiliti daca sunt echivalente inecuatiile rezolvate in multimea numerelor intregi: a) $\frac{5x-3}{2} - \ \frac{2x}{3} +1 \leq \frac{x+13}{6} -x$
, si inecuatia
3x-10< 2x+(-2)³

b) $\frac{2x-1}{3} + \frac{5x}{12} - \frac{x-3}{4} \ \textgreater \ \frac{5x-2}{6}$  si inecuatia $0,3x-0,(3) \leq 0,1x+0,2x$

Answer 1

Pe prima nu o ştiu... scuze

$3x-10<3x+{ (-2) ^{3} }$
3x-10<2x-8
3x-2x<-8+10
x<2
x aparţine 0 ; 1

Aduci peste tot la acelaşi numitor: 12. Amplifici cu cât este nevoie pentru a ajunge la 12.
4(2x-1)+5x-3(x-3)>2(5x-2)
8x-4+5x-3x+9>10x-4
8x+4x-3x+8>10x
10x+9>10x
9>0
x aparţine R

$0,3x-0,3 \leq 0,1x+0,2x$
$0,3x-\dfrac{1}{3} \leq 0,21x$
$0,3x-0,21x \leq \dfrac{1}{3}$
$0,09x \leq \dfrac{1}{3}$
$x \leq \dfrac{1}{3}:0,09$
$x \leq \dfrac{1}{3} : \dfrac{9}{100}$
$x \leq \dfrac{1}{3} \cdot \dfrac{100}{9}$
$x \leq \dfrac{100}{27}$