Question

Va rog frumos ,am nevoie urgent....
Daca x= ( 1+\frac{1}{2} +1,1(6)+1,(3) ) · 1,5² si

y= 2,5 : 20 + (\frac{1}{2} + \frac{3}{9} + \frac{1}{6} ) · \frac{7}{8} , calculati :

a). x ² + y ²⁰¹⁵ ;

b). Media aritmetica a numerelor x si y.

Answer 1

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Answer 2

$x=(1+ \frac{1}{2} +1,1(6)+1,(3))*1,5^{2}$
$y=2,5:20+(\frac{1}{2}+\frac{3}{9}+\frac{1}{6})*\frac{7}{8}$

$x=(1+ \frac{1}{2} +\frac{116-11}{90}+\frac{12}{9})*\frac{225}{100}$
$x=(\frac{90}{90}+ \frac{45}{90} +\frac{105}{90}+\frac{120}{90})*\frac{225}{100}$
$x=(\frac{90+45+105+120}{90})*\frac{225}{100}$
$x=\frac{360}{90}*\frac{225}{100}$
$x=\frac{4*225}{100}$
$x=9$

$y= \frac{25}{10*20}+( \frac{9}{18}+ \frac{6}{18}+\frac{3}{18})*\frac{7}{8}$
$y= \frac{1}{8}+\frac{18}{18}*\frac{7}{8}= \frac{8}{8}=1$

a)$x^{2} +y^{2015}= 81+1= 82 b) media = [tex] \frac{9+1}{2} = 5$