Question

va rog frumos, am nevoie urgentă de ajutor la aceste cerințe!!!

Answer 1

Răspuns:

Explicație:

1.

MCaCl2 =  40 + 2 . 35,5 = 111---------> 111g/moli

MAgNO3 = 108 + 14 + 3 .16 = 170 -------> 170 g/moli

2

CaCl2

r.a.= 1 : 2

r.m.= 40 : 71

AgNO3

r.a. = 1 : 1 : 3

r.m.= 108 : 14 : 48= 54 : 7  : 24

3 COMP. PROC.PRIN MASA MOLARA

CaCl2

111 g CaCl2------------40g Ca-----------71 g Cl

100 g---------------------x------------------------y

x= 100 . 40 : 111 =36,036 % Ca

y= 100 .71 : 111 =63,97% Cl

AgNO3

170 g AgNO3--------108g Ag---------14gN---------48 g O

100g ---------------------x-----------------------y-----------z

x= 100. 108 : 170=63,52% Ag

y= 100. 14 : 170= 8,24% N

z= 100.48 : 170=28,24% O