Question

Vă rog frumos! Am test mâine. ​

Answer 1

4Al(0) + 3O2(0) ---> 2Al2(3+)O3(2-)

2x l Al(0)__-3e-__> Al(3+) oxidare (ag. red.)

3x l O(0) _+2e-__> O(2-) reducere (ag. oxid.)

2H2(+)S(2-) + 3O2(0) ---> 2S(4+)O2(2-) + 2H2(+)O(2-)

1x l S(2-) _-6e-_> S(4+) oxidare (ag. red.)

3x l O(0) _+2e-_> O(2-) reducere (ag. oxid.)

2P4(0) + 10O2(0) ---> 2P4(5+)O10(2-)

2x l P(0) _-5e-_> P(5+) oxidare (ag. red.)

5x l O(0) _+2e-_> O(2-) reducere (ag. oxid.)