Question

Va rog frumos dau coroana

Answer 1

a)$log_{2}x= log_{2} \frac{64}{16} \\ log_{2} x= log_{2}4 \\ x=4 \\ b) log_{ \sqrt{7} }x= log_{ \sqrt{7} }16 - log_{ \sqrt{7} }2+ log_{ \sqrt{7} }5$
$log_{ \sqrt{7} }x= log_{ \sqrt{7} } \frac{16}{2}*5 \\ x=40 \\ c) log_{4} x+ log_{16}x+ log_{2}x=7$
$log_{2}x+ log_{2} \sqrt{x} + log_{2} \sqrt[4]{x}=7 \\ x* \sqrt{x} * \sqrt[4]{x}=128 \\ x^{ \frac{7}{4} }=128$
$x^{ \frac{1}{4} }= 2 \\ x=16$