Question

va rog frumos dau coroana

Answer 1

3) a)

($(7^{2}- 3^{2} ):5^{1}= (49-9):5 = 40:5 = 8 \\ (30^{2}- 29^{2}):59=(30-29)*(30+29):59=59:59=1 \\ (2+2*3)^{2}:2^{4}=8^{2}: 2^{4}= 64:16 = 4 \\ (4^{3}- 8^{2}): 7^{48}= [(2^{2}) ^{3} - (2^{3}) ^{2}]:7^{48}=(2^{6}-2^{6}):7^{48}=0:7^{48}=0$

b)

$(3^{2}+10*3^{2}):11=(9+90):11=99:11=9 \\ (2^{4}-4^{2})*5^{6}=(2^{4}-2^{4})*4^{6}=0*5^{6}=0\\ 6^{4}-6^{4}*3^{0}=6^{4}-6^{4}*1=6^{4}-6^{4}=0\\6^{2}:4-4=36:4-4=9-4=5$