Question

VA ROG FRUMOS!DAU COROANA

Answer 1

$a) {10}^{2} \times ((4 + 5 \times {3}^{2} - {2}^{5} + {4}^{3} \times (49 - {3}^{2} ) \div {2}^{3} ) \\ = 100 \times ((4 + 5 \times 9 - 32 + 64 \times (49 - 9) \div 8) = \\ = 100 \times (4 + 45 - 32 + 64 \times 40 \div 8) = \\ = 100 \times (49 - 32 + 2560 \div 8) \\ = 100 \times (17 + 320) = 100 \times 337 = 33700$

$b)(( {2}^{6} ) ^{4} \div {2}^{3} \times ( {2}^{6} + {2}^{6} ) - {4}^{6} \div {2}^{10} ) \div ( {2}^{28} - {2}^{2} ) + 9 \\ = (( {2}^{24} \div {2}^{ 3} \times 2 \times {2}^{6} - ({2}^{2} ) ^{6} \div {2}^{10} ) \div ( {2}^{28} - {2}^{2} ) + 9 \\ = ( {2}^{24 - 3 + 1 + 6} - {2}^{12} \div {2}^{10} ) \div ( {2}^{28} - {2}^{2} ) + 9 = \\ = ( {2}^{28} - {2}^{2} ) \div ( {2}^{28} - {2}^{2} ) + 9 = \\ = 1 + 9 = 10$