Question

Vă rog frumos !!!Dau coroana

Answer 1

Răspuns:

a.

m(AOB)=2x

m(BOC)=3x

m(COD)=4x-60

m(DOA)=4x+30

Fiind unghiuri in jurul unui punct, suma lor este de 360 => 2x+3x+4x-60+4x+30=360=>

13x-30=360 => 13x=390 => x=30 grade

m(AOB)=2x=2*30=60 grade

m(BOC)=3x=3*30=90 grade

m(COD)=4x-60=4*30-60=60 grade

m(DOA)=4x+30=4*30+30=150 grade

b.

[OM-bisect < AOB => m(AOM)=m(MOB)=30 grade

[ON-bisect < BOC => m(BON)=m(NOC)=45 grade

=> m(MON)=m(MOB)+m(BON)=30+45=75 grade

꧁Sper ca te-am ajutat!꧂