Question

Vă rog frumos!Dau coroana!Punctele semnate.​

Answer 1

5.

d)x^2 + 3x + 4x + 12 =

x(x+3) + 4(x+3) =

(x+3)(x+4)

e)x^2 + 2x + 4x + 8 =

x(x+2) + 4(x+2) =

(x+2)(x+4)

6.

d)x^2 - 2x - 3x + 6 =

x(x-2) - 3(x-2) =

(x-2)(x-3)

f)x^2 - 2x - 6x + 12 =

x(x-2) - 6(x-2) =

(x-2)(x-6)

Answer 2

$5. {x}^{2 } + 7x + 12 = {x}^{2} + 4x + 3x + 12 = x \times (x + 4) + 3(x + 4) = (x + 4)(x + 3)$

${x}^{2} + 6x + 8 = {x}^{2} + 4x + 2x + 8 = x \times (x + 4) + 2(x + 4) = (x + 4)(x + 2)$

$6. {x}^{2} - 5x + 6 = {x}^{2} - 2x - 3x + 6 = x \times (x - 2) - 3(x - 2) = (x - 2)(x - 3)$

${x}^{2} - 8x + 12 = {x}^{2} - 2x - 6x + 12 = x \times (x - 2) - 6(x - 2) = (x - 2)(x - 6)$