Question

Va rog frumos! Dau o gramada de puncte, coroana, si follow!
$\sqrt { 5 } + ( \frac { 1 } { \sqrt{5} } + \frac { 1 } { \sqrt { 2 } } ) \cdot \sqrt { 10 } - ( \frac { 1 } { \sqrt { 8 } } - \frac { 1 } { \sqrt { 20 } } ) \cdot 4 \sqrt { 10 } - 5 \sqrt { 2 }\\ 4 \sqrt { 7 } + ( \frac { 2 } { \sqrt { 7 } } + \frac { 1 } { \sqrt { 5 } } ) \cdot \sqrt { 35 } - ( \frac { 1 } { \sqrt { 125 } } - \frac { 1 } { \sqrt { 175 } } ) \cdot 25 \sqrt { 35 } - 7 \sqrt { 5 } \\ \frac { \sqrt { 12 } - \sqrt { 8 } } { \sqrt { 24 } } + \frac { \sqrt { 6 } - \sqrt { 9 } } { \sqrt { 18 } } + \frac { \sqrt { 8 } - \sqrt { 20 } } { \sqrt { 40 } } + \frac { \sqrt { 30 } - \sqrt { 12 } } { \sqrt { 60 } }$
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Answer 1

Explicație pas cu pas:

ultima nu o știu, sper ca team ajutat cu ce am putut

Answer 2

$\it \dfrac{\sqrt a}{\sqrt b}=\sqrt{\dfrac{a}{b}}\\ \\ \\ \dfrac{\sqrt{12}+\sqrt{8}}{\sqrt{24}}+\dfrac{\sqrt6-\sqrt9}{\sqrt{18}}+\dfrac{\sqrt8-\sqrt{20}}{\sqrt{40}}+\dfrac{\sqrt{30}-\sqrt{12}}{\sqrt{60}}=\\ \\ \\ =\dfrac{\sqrt{12}}{\sqrt{24}}-\dfrac{\sqrt{8}}{\sqrt{24}}+\dfrac{\sqrt{6}}{\sqrt{18}}-\dfrac{\sqrt{9}}{\sqrt{18}}+\dfrac{\sqrt{8}}{\sqrt{40}}-\dfrac{\sqrt{20}}{\sqrt{40}}+\dfrac{\sqrt{30}}{\sqrt{60}}-\dfrac{\sqrt{12}}{\sqrt{60}}=$

$\it = \dfrac{1}{\sqrt2} -\dfrac{1}{\sqrt3}+\dfrac{1}{\sqrt3} -\dfrac{1}{\sqrt2} +\dfrac{1}{\sqrt5}-\dfrac{1}{\sqrt2} +\dfrac{1}{\sqrt2} -\dfrac{1}{\sqrt5} = 0$