Question

va rog frumos, ex 3 fig 34

Answer 1

m(EOF)=x
m(DOE)=x+16
31+94+41+x+16+x+80=360
2x=360-262
2x=98
x=49
m(EOF)=49
m(DOE)=49+16=65
m(DOF)=49+65=114

Answer 2

m(DOF)= 360 - 31 -94 - 41 - 80 = 114 GRADE PESTE TOT SI UNGHI

notam cu x=m(EOF)
AVEM m(DOE)=x+16
m(DOF)=m(DOE)+m(EOF)
x+16 +x =114
2x+16=114
2x=114-16
2x=98
x=49=m(EOF)