Question

va rog frumos. rapid. dau coroana. va rooogggg doar cele incercuitesi ex 9 tot​

Answer 1

Răspuns:

Explicație pas cu pas:

6)

b)

1/512= (1/2)⁹

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c)

125/27=(5/3)³

d)

81/256=3⁴/4⁴

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e)

(0)ⁿ ..........0 ridicat la orice putere este 0

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7)

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b)

(1/7)ⁿ=1/343= 1/7³=(1/7)³→n=3

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c)

1¹/₂=(1*2+1)/2=3/2

(3/2)ⁿ=3³⁷⁵/₁₀₀₀=75⁽⁵/200⁽⁵= 15⁽⁵/40⁽⁵=3/8=3³/₈=(3*8+3)/8= 27/8=(3/2)³→n=3

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e)

(1/3²)ⁿ=1/729= (1³/9³)=(1/9)³→n=3

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f)

(1/8)ⁿ=1/4³=(1/64)=(1/8)²→n=2

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8)

c)

= (³⁾1/2+²⁾1/3+1/6)²⁰¹¹:(4⁽⁴/12⁽⁴)²

=(3/6+2/6+1/6)²⁰¹¹:(1/3)²

= (6/6)²⁰¹¹:(1/3)²

= 1²⁰¹¹: 1/9

= 1*9

= 9

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d)

=[(³⁾1/3-1/9)²+(1/3)³]:(1/3)⁴

= [ (3/9-1/9)²+(1/3)³]:(1/3)⁴

= [(2/9)²+(1/27)]:( 1/3)⁴

=[( 4/81+³⁾1/27)]: ( 1/81)

= (4/81+3/81):(1/81)

= 7/81⁽⁸¹*81⁽⁸¹/1

=7*1

=7

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9)

a)

(3/5)¹⁵=p⁵

(3/5)¹⁵=[(3/5)³]⁵= (27/125)⁵→p= 27/125

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(3/5)¹⁵=q³

(3/5)¹⁵=[(3/5)⁵]³=(243/3125)³→q= 243/3.125

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b)

(3/7)⁶=p²

[(3/7)³]²= (27/343)²→p=27/343

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(3/7)⁶=q³

[(3/7)²]³=( 9/49)³→q= 9/49

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c)

(1/2)¹⁰=p⁵

[(1/2)²]⁵= (1/4)⁵→p=1/4

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(1/2)¹⁰=q²

[(1/2)⁵]²= (1/32)²→q= 1/32

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d)

(1/3)⁸=p⁴

[(1/3)²]⁴= (1/9)⁴→p= 1/9

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(1/3)⁸=q²

[(1/3)⁴]²= (1/81)²→q=1/81

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