Question

va rog frumos repede!!

Answer 1

Răspuns:

Explicație:

1.

a.       Mg(PO3)2

r. a. = 1Mg : 2 P : 6 O= 1  : 2 : 6

M= 24 + 2.31 + 6.16= 182 ------> 182g/moli

b.       CuCO3

r.a.= 1 : 1 : 3

M= 64 + 12 + 3.16=124-------> 124g/moli

2.

M Na2SO4= 2.23 + 32 + 4.16=142 ------> 142g/moli

142g Na2SO4--------32 g S

568g ---------------------x

x= 568 . 32 : 142 = 128 g S

3.

MH2 SO4= 2 + 32 + 4.16 = 98-----> 98g/moli

n= 392g : 98g/moli = 4 moli H2SO4

1mol H2SO4-------6,022.10²³ molecule H2SO4

4moli---------------------y

y= 4 . 6,022.10²³ = 24,088 .10²³molecule H2SO4

4.

K2SO4

M= 2.39 + 32 + 4.16=174 ------> 174 g/moli

174g K2SO4-------78g K-------32 g S--------64 g O

100 g---------------------x-------------y--------------z

x= 100 . 78 : 174 = 44,83 % K

y= 100 .32 : 174 = 18, 39 g S

z= 100 . 64 : 174 = 36, 78 % O