Question

Va rog frumos repede

Answer 1

V1= 500 cm3 , c1%= 60% , p= 1,503 g/cm3

V2= 3616 cm3 , c2= 88% , p= 1,808 g/cm

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Cm.finala= ? M

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stim ca Cm= md/MxVs

Vs.final = V1 + V2 = 500+3616 = 4116 cm3 = 4,116 L

c% = mdx100/ms

p = ms/Vs

=> ms1 = p1xV1 = 500x1,503 = 751,5 g

=> ms2 = p2xV2 = 3616x1.808 = 6537,73 g

=> md1= ms1xc1/100 = 751,5x60/100 = 450,9 g

=> md2= ms2xc2/100 = 6537,73x88/100 = 5753,2 g

=> md.final = md1 + md2 = 6204,10 g

M(H2SO4) = 2x1+32+4x16 = 98 g/mol

=> Cm = md.final/M(H2SO4)xVs.final

= 6204,10/98x4,116 = 15,38 M