Question

Va rog frumos repede aceste ex sau coroana ​

Answer 1

Asa am invatat eu:

6 rad din 2=rad din 6 ori 6 ori 2=rad din 72

8 rad din 3=rad din 8 ori 8 ori 3=rad din 192

9 rad din 2=rad din 9 ori 9 ori 2=rad din 162

Cred ca ai inteles. Nu e greu .Sper sa te descurci mai departe.

Answer 2

Răspuns:

1.

a)

$6 \sqrt{2} = \sqrt{ {6}^{2} \times 2} = \sqrt{72}$

$8 \sqrt{3} = \sqrt{ {8}^{2} \times 3} = \sqrt{192}$

$9 \sqrt{2} = \sqrt{ {9}^{2} \times 2 } = \sqrt{162}$

$5 \sqrt{6} = \sqrt{ {5}^{2} \times 6 } = \sqrt{150}$

$7 \sqrt{3} = \sqrt{ {7}^{2} \times 3 } = \sqrt{147}$

$4 \sqrt{7} = \sqrt{ {4}^{2} \times 7} = \sqrt{112}$

$- 10 \sqrt{3} = - \sqrt{ {10}^{2} \times 3 } = - \sqrt{300}$

$- 12 \sqrt{5} = - \sqrt{ {12}^{2} \times 5 } = - \sqrt{720}$

b)

$- \frac{3}{4} \sqrt{3} = - \sqrt{ (\frac{3}{4} )^{2} \times 3 } = - \sqrt{ \frac{27}{16} }$

$- \frac{4}{9} \sqrt{5} = - \sqrt{ \frac{80}{81} }$

$- \frac{2}{3} \sqrt{7} = - \sqrt{ \frac{28}{9} }$

$- 5 \sqrt{7} = - \sqrt{175}$

$- 6 \sqrt{5} = - \sqrt{180}$

$- 4 \sqrt{2} = - \sqrt{32}$

$7 \sqrt{10} = \sqrt{490}$

c)

$5 \sqrt{14} = \sqrt{350}$

$- 3 \sqrt{15} = - \sqrt{135}$

$- 8 \sqrt{6} = - \sqrt{384}$

$17 \sqrt{3} = \sqrt{867}$

$- 9 \sqrt{10} = - \sqrt{810}$

$12 \sqrt{6} = \sqrt{864}$

$- 6 \sqrt{7} = - \sqrt{252}$

$- 14 \sqrt{2} = - \sqrt{392}$

d)

$12 \sqrt{7} = \sqrt{1008}$

$13 \sqrt{5} = \sqrt{845}$

$- 11 \sqrt{6} = - \sqrt{726}$

$- \frac{8}{5} \sqrt{3} = - \sqrt{ \frac{192}{25} }$

$- \frac{5}{12} \sqrt{2} = - \sqrt{ \frac{50}{144} } = - \sqrt{ \frac{25}{72} }$

$18 \sqrt{3} = \sqrt{972}$

$- 15 \sqrt{2} = - \sqrt{450}$

2.

a) E foarte simplu, urmează exemplul pe care ți l-am dat!

b) La fel.

c)

$- 11 \sqrt{6} = - \sqrt{726}$

$- 5 \sqrt{3} = - \sqrt{75}$

$- \frac{7}{2} \sqrt{2} = - \sqrt{ \frac{98}{4} } = - \sqrt{ \frac{49}{2} }$

d)

$\frac{3}{7} \sqrt{3} = \sqrt{ \frac{27}{49} }$

$0.(3) \sqrt{21} = \sqrt{ \frac{21}{9} } = \sqrt{ \frac{7}{3} }$

$0.(1) \sqrt{6} = \sqrt{ \frac{6}{81} } = \sqrt{ \frac{2}{27} }$

$- 0.(6) \sqrt{15} = - \sqrt{ \frac{60}{9} } = - \sqrt{ \frac{20}{3} }$

$0.(4) \sqrt{63} = \sqrt{ \frac{1008}{81} } = \sqrt{ \frac{112}{9} }$