Question

va rog frumos , repede, dau coroana

Answer 1

√3(9/√54-4/√24)-√2(8/√96-18/√216)+1/12(√12-√32) =

= √3(9/3√6-4/2√6)-√2(8/4√6-18/6√6)+1/12(2√3-4√2) =

= √3(3/√6-2/√6)-√2(2/√6-3/√6)+1/12*2(√3-2√2) =

= √3*1/√6-√2(-(1/√6)+1/6*(√3-2√2) =

= 1/√2+1/√3 +√3/6-√2/3 =

= √2/2+√3/3+√3/6-√2/3 =

= √2/6 + √3/3 + √3/6 = √2/6 + √3/2

Answer 2

rad 3 (9/ rad 54 - 4/ rad 24) - rad 2 (8/rad 96 - 18/rad 216) + 1/12 (rad 12 - rad 32) = 
= rad 3 (9/3 rad 6 - 4/2 rad 6) - rad 2 (8/4 rad 6 - 18/6 rad 6) + 1/12 (2 rad 3 - 4 rad 2) = 
= rad 3 (3/rad 6 - 2/rad 6) - rad 2(2/rad 6 - 3/rad 6) + 2/12(rad 3 - 2 rad 2) = 
= rad 3 * 1/rad 6 - rad 2 * (-1/rad 6) + 1/6 (rad 3 - 2 rad 2) = 
= 1/ rad 2 + 1/ rad 3 + rad 3/6 - rad 2/3 = 
= rad 2/2 + rad 3/3 + rad 3/6 - rad 2/3 = 
= 3 rad 2/6 - 2 rad 2/6 + 2 rad 3/6 + rad 3/6 = 
= rad 2/6 + 3 rad 3/6 = rad 2/6 + rad 3/2